Divide the 3-4-5 triangle to two triangles
with equal inradii: three solutions

The coordinates of the vertices of the triangle ABC:
C{0,0}, B{3,0}, A{0,4}.

[Graphics:Images/2circ_gr_2.gif]

[Graphics:Images/2circ_gr_3.gif]

No, these three lines do not meet in one point (and why they should?)

I thank Steve Brian for pointing me the typho in the previous coordinates of D.

See also the case of "arbitrary" triangle with a = 4, b = 2, c = 3.